5r^-3 s^-6 for r=3 and s=0

Question

5r^-3 s^-6 for r=3 and s=0

Answer 1

5r^(-3)s^(-6) = 5 / (r^3s^6) 

 

If you plug in r = 3 you get 5 / (27s^6)

 

If you try to plug in 0 for s you will get 0 in the denominator and your quantity will be undefined