j,k,l are three consecutive positive integers .j+k=even and k-l is natural number ?

Question

choice is given j is greater or k?

Answer 1

Since k-l is a natural number then k-l>0 or k>l.

Also since j+k is even then we know that either j and k are both even or odd. Hence are at least two apart.

Thus since j,k, and l are consecutive numbers then j<l<k.