Find the equation perpendicular to the line y=−3x+5 that passes through point (2, 6).

Question

 yeetttt

Answer 1

Perpendicular means the slope are negative reciprocal ( change the sign and flip the slope)

 

Y = mx + b  (m is the slope which is -3 = -3/1 in your )

 

Perpendicular slope would be +1/3

 

Using Y = mx +b  we know the perpendicular slope now, so plug in

       Y = (1/3)x + b   (2,6) is a point (x,y) so plug in

      6 = (1/3)(2) + b

     6  = 2/3 + b      multiplied by 2

   -2/3   -2/3        subtract -2/3 on both sides

   16/3 = b

 

So y = (1/3)x + 16/3

Answer 2

equation perpendicular to the line y=−3x+5 that passes through point (2, 6)

The perpendicular line will have a slope that is opposite sign and inverse, so, the new slope will be 1/3

y = 1/3(x) + b

6 = 1/3(2) + b

6 = 2/3 + b

18 = 2 + 3b

16 = 3b

b = 16/3 

y = 1/3(x) + 16/3

or,

3y = x + 16