Alexa C.

asked • 08/26/18

Combustion reaction

40% of a liquified petroleum gas is composed of propane and the rest is butane. This mixture is put into a room which has a size of 2m x 3m x 4m. How many grams of this mixture can be burned with the air in this room at STP? (remember that 21% of air by volume is oxygen) 

Lauren H.

Alexa, is this the entire text of the question?  If the room is full of air at STP before addition of the LPG, then, when LPG is added, either the pressure will increase so that the room is no longer at STP, or, some air must be removed.  It's difficult to solve this when you don't know how much air was removed as LPG was added, assuming the system remained at STP.


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