A 75 kg child clombs a 6.00 m long slide that is inclined at 30° with the horizontal. What is the potential energy of the child with respect to the ground?

Question

Use one of the formulas for solving Potential Energy

Answer 1

PE = mgh = mg(L sinθ)

 

m = 75 kg

g = 9.8 m/s²

L = 6.00 m

θ = 30°

 

PE = (75)(9.8)(6.00 sin30°) kg m/s² = 2205 joules

 

Answer 2

6/sin90 = h/sin30

6sin90 = hsin30

6 = 0.5h

h = 12

 

PE = 75(9.8)(12) = 8820 J