Mark M. answered 07/12/18
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Let x = length (in cm) of the decreasing leg at time t seconds
y = length (in cm) of the increasing leg at time t seconds
A = area of triangle at time t seconds
Given: dx/dt = -3 dy/dt = 4
Find: dA/dt when x = 8 and y = 5
Since A = (1/2)xy, we have dA/dt = (1/2)[x(dy/dt) + y(dx/dt)]
= (1/2)[(8)(4) + (5)(-3)]
= 8.5 square cm/sec
When x = 8 cm and y = 5 cm, the area of the triangle is increasing at the rate of 8.5 square cm/sec.