J.R. S. answered 06/08/18
Tutor
5.0
(145)
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
Write the balanced equation:
CoSO4(aq) + Na2CO3(aq) ==> CoCO3(s) + Na2SO4(aq)
mass of precipitate (CoCO3) = 8.98g - 1.04 g = 7.94 g
moles of CoCO3 = 7.94 g x 1 mole/119 g = 0.0667 moles
moles of CoSO4 = 0.0667 moles since balanced equation shows a mole ratio of 1:1 for CoSO4 : CoCO3
Concentration of CoSO4 = 0.0667 moles/0.1000 L = 0.667 M (to 3 significant figures)