
Bobosharif S. answered 05/21/18
Tutor
4.4
(32)
Mathematics/Statistics Tutor
If you have written every correctly, then as a real solution you can take any linear function
y(x)=ax+b, a, b constant (unknown)
Indeed the solution is (you twice integrate ±10i)
y1(x)=-5i x2+C1x+C2
y2(x)=5i x2+C1x+C2
y(x)=y1(x)+y2(x)=C'1x+C'2 is a real solution