solve each equation

Question

1/b-2 + 1/3b-2 = b+2/b-2

Answer 1

1/(b-2) + 1/(3b-2) = (b+2)/(b-2)

 

1/(3b-2) = (b+2)/(b-2) - 1/(b-2)

 

1/(3b-2) = (b+1)/(b-2)

 

(3b-2)(b+1) = b-2

 

3b^2 + 3b - 2b - 2 = b-2

 

3b^2 + b - 2 = b-2

 

3b^2 + b - 2 - b + 2 = 0

3b^2 =0

b=0

 

CHECK:

1/(0-2) + 1/(3*0-2) = (0+2)/(0-2)

 

- 1/2  + -1/2  = 2/-2

 

 -1 = -1

 

Yes it works.

 

b = 0