
Andy C. answered 02/15/18
Tutor
4.9
(27)
Math/Physics Tutor
y = 5x - 12
x = 5y - 12
(x+12)/5 = y
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y = x^10
x = y^10
y = x^(1/10)
BUT IF you meant y = x^2 + 8 then
x = y^2 + 8
(x-8) = y^2
y = sqrt(x-8)
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y = 10x - 6/11
x = 10y - 6/11
(x+6/11) = 10y
y = (1/10)(x + 6/11)
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y = cube_root(4)*x + 12
x = cube_root(4)*y + 12
(x - 12) = cube_root(4)*y
4^(2/3)*(X-12) = 4*y
y = 4^(2/3)(x-12)/4
BUT IF you meant y= cube_root(4x) + 12 THEN
x = cube_root(4y) + 12
(x-12) = cube_root(4y)
(x-12)^3 = 4y
y = (x-12)^3/4
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y = (x-27)^3
x = (y-27)^3
cube_root(x) = y - 27
y = cube_root(x) + 27