chemistry help-molar mass

Question

From the data in the table below, calculate the molar mass of the aluminum. Aluminum reacts with hydrochloric acid according to the balanced chemical equation below.

2AL (s) + 6HCl (aq) → 2AlCl₃ (aq) + 3H₂ (g)
Mass of Sample

13.1 g

Number of Moles of H2

0.72 mol

Answer 1

2Al(s) + 6HCl(aq) ==> 2 AlCl3(aq) + 3H2(g)

I don't know what your question is, and no table is given, but here are some calculations that may help

Assuming HCl is present is excess, one can find the mass of AlCl3 produced and the amount of H2 also.

13.1 g Al x 1 mol/27.0 g = 0.486 moles Al(s)

moles AlCl3 produced = 0.486 moles Al x 2 moles AlCl3/2 moles Al = 0.486 moles AlCl3 produced

mass of AlCl3 produced = 0.486 moles x 133 g/mol = 64.5 g AlCl3

moles H2 produced = 0.486 moles Al x 3 moles H2/2 moles Al = 0.729 moles H2 gas produced

There are other calculations, but I don't know what you need.  Calculation of molar mass is not a calculation that can be performed with the information given.