
McKenzie S. answered 10/05/17
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x = 30
μ = 26.8
σ = 7.4
P(X ≥ x) = 1 - P[(X-μ)/σ < (x-μ)/σ]
μ = 26.8
σ = 7.4
P(X ≥ x) = 1 - P[(X-μ)/σ < (x-μ)/σ]
P(X ≥ 30) = 1 - P[Z < (30-26.8)/7.4] = 1 - P(Z < 0.43)
From the table of normal distribution for z = 0.43, we get 0.666402.
So, 1 - 0.666402 = 0.333598