eliminate theta from the relation a sec theta=1-b tan theta and a square sec square theta=5+b square tan square theta

Question

pls answer to this question  urgent...

Answer 1

I think your equations are

asecΘ = 1-btanΘ

a²sec² Θ = 5+b²tan²Θ

 

You can use the identity tan² Θ + 1 = sec ²Θ and you can replace in the second equation

it becomes a²(tan² Θ+1) = 5 + b²tan² Θ

a²tan² Θ - b²tan² Θ = 5 - a^2

tan² Θ ( a²-b²) = 5-a²

tan Θ = (5-a²)/(a²-b²)

Θ = tan ^-1 [ (5-a²)/(a² - b²)

You can now substitute this into the first equation

 

Hope this helped