Lily L.

asked • 06/03/14

how do i set up the area equation of the outside rectangle if length is "x" and width is 14. And inside of the rectangle: length is 12 and width is x-4? I don't

how do i set up the area equation of the outside rectangle if length is "x" and width is 14. And inside of the rectangle: length is 12 and width is x-4? I don't know how to see it up. I know the formula is A=l times w. The hint says: find the area of the outside rectangle and subtract the area of the inside rectangle. 

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PIYUSH L. answered • 06/03/14

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Lily L.

Find the equations of the areas of these rooms and find the area of these photo frames. (Hint: find the area of the outside rectangle and subtract the area of the inside rectangle. The outside length is "x" and the outside width is 14. The inside of the frame, the length is 12 and width is x-4. 
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06/03/14

PIYUSH L.

Based on the information you provided, I will try to answer it to the best of my understanding.
As you already know area of rectangle is defined by l*b
Area of outside rectangle =  x * 14
Area of inside rectangle = 12*(x-4)
Area of photo frame = x * 14 - 12*(x-4) = 2x +48
 
Also width of outside triangle > width of inside triangle
14 > x-4
18>x
 
length of outside triangle > length  of inside triangle
x>12
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06/03/14

Lily L.

How did you get the 2x+48?
 
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06/03/14

PIYUSH L.

Here it is 
 
Area of outer triangle = 14*x=14x
Area of inner triangle = 12*(x-4)=12x-48
Difference = 14x -(12x-48) = 14x-12x+48 = 2x+48
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06/03/14

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