Log(x+3)^(2x+3)+log(x+3)^(x+5)=2

Question

How do I solve this problem Step by step?

Answer 1

Log ( X +3 ) ^ ( 2X + 3 ) + Log ( X + 3 ) ^ ( X +5 ) = 2

 

  ( 2X + 3 ) Log ( X+3 ) + ( X +5 ) log ( X +3 ) =Log 2

 

  Log ( X + 3 ) - Log 2 = ( 2X +3 +X + 5 ) 

 

   log X +3   = 3X + 8 

          2

      X + 3 = 10 ^{3X + 8} 

         2

       This is as far as can go to simplify.