Tyler M.
asked • 02/26/14
3x^2+26+48
Inactive Tutor
answered • 02/26/14
May be the question is solve
3x2 + 26x + 48 =0
3x2 +18x + 8x +48 = 0
3x(x+6) + 8(x+6) = 0
(3x+8)(x+6) = 0
3x + 8 = 0. x= -8/3
or
x+6 = 0 , x = -6
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