
Arturo O. answered 10/31/16
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The amount of carbon-14 present obeys an exponential decay law.
A(t) = A(0)e-kt
Get k from the half-life:
0.5 = 1e-k(5600)
k = ln(0.5) / (-5600 years) = 1.2378 x 10-4 years-1
If only 73% of the carbon-14 remains after time T, then
0.73 = 1e-kT
T = ln(0.73) / (-1.2378 x 10-4 years-1) = 2542.5 years
The tree has been dead for about 2542.5 years.