Kenneth S. answered 10/05/16
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
So they both go the same distance.
Let the time of the fast car be t hours; that means the slower car must have traveled for t+3 hours.
Since distance = rate multiplied by time for each vehicle, we have
60(t) = 30(t+3). Do you see why?
When you do, you will see that this equation can be solved for t.
Then plug the value of t into either of the above two equal expressions, to find the total distance they traveled, which is the answer to "how far from the starting point are..."