
James B. answered 06/23/16
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Let n = number of day
Let t = temperature
HEARTHTOWN:
On Jan 1, temp is 88°. ... on Jan 4 (3 days later), it is 82° ...88 - 2(3) = 82° ... it drops 2° per day
So, this equation represents the temperature, n days after Jan 4th
t = 82 - 2n ... starting temperature is 82°, and it falls 2° per day
POLK:
On Jan 4, temp is 52. It rises 4° per day
t = 52 + 4n
The temperatures will be the same a single value of n produces the same temperature for both equations
52 + 4n = 82 - 2n
4n + 2n = 82 - 52
6n = 30
n = 5
The temperatures will be the same 5 days after Jan. 4th.
The temperatures will be 72° on January 9th