(8m7c9)(3m9c7)

Question

Where do I begin to solve this?

 

Answer 1

 It seems like numbers are exponents , you should write as Superscript or use( ^ ) , m6 is written normally as 6m.

 

       (8 m⁷ c ⁹ ) ( 3 m⁹c⁷) = 24 m¹⁶ c¹⁶  / multiplication of exponent with the same base, same base with

                                                                exponent as sum.    

 

Answer 2

Break up one factor into individual factors and then multiply, as follows:

 

(8m7c9)(3m9c7) = (8m7c9)(3)(m)(9)(c)(7)

 

                         = {(8m7c9)(3)} (m)(9)(c)(7)

 

Note that (8m7c9)(3) = (8m7c9)+(8m7c9)+(8m7c9)

                               = (24m7c9)

 

Similarly (24m7c9)(m) = (24m7c9) + (24m7c9) + ...m times

                                 = (24(m^2)7c9)

 

Continuing gives (8m7c9)(3m9c7)= 24*(m^2)*63*(c^2)*63

                                                 =24*63*63*(m^2)*(c^2)

       

                                                 = 95256*(m^2)*(c^2)

 

Note that if the first term (8m7c9) were the sum (8+m+7+c+9) then the indivdual factors of (3m9c7) would be distributed among each item in (8+m+7+c+9), ie

 

(8+m+7+c+9)*3 would equal (24+3m+21+3c+27) ... and so forth for the other factors of (3m9c7).

BDS