Find the dimensions of a rectangle whose length is a foot longer than twice its width and whose perimeter is 26 feet.

Question

How do you get length and width with this?

Answer 1

w=width

2w+1=length

 

P=2l+2w

26=2(2w+1)+2w

26=4w+2+2w

26=6w+2

26-2=6w

24=6w

w=24/6

w=4 feet

l=2(4)+1=8+1=9 feet