Solve algebraically 5x^2/4=2(x-1)

Question

Solve algebraically : 5x^2/4=2(x-1)

Answer 1

5x²/4=2(x-1) or (5/4)x²-2(x-1) or (5/4)x²-2x+2=0

Multiply by 4 to get 5x²-8x+8=0 now use the quadratic formula

x=(8±√[64-4(5)(8)])/10

x=(8±√-96)/10 = (8±4i√6)/10 =(4±2i√6)/5

Answer 2

5x^2/4 = 2(x-1)

Multiply both sides by 4, yields:

5x^2 = 8(x-1)

Distribute the 8, yields:

5x^2 = 8x-8

draw all terms to left side, yields:

5x^2 + (-8)x + 8 = 0

a = 5; b = -8; c = 8

Apply Quadratic Formula:

[-b ± (b^2 - 4ac)^(1/2)] / (2a)