
Robert J. answered 10/30/13
Tutor
4.6
(13)
Certified High School AP Calculus and Physics Teacher
f(x) = ln(x-1)/ln5 - 4, using the change of base formula
f'(x) = 1/[(x-1)ln5)]
So, the critical point is at x = 1, and the domain is x > 1 since x-1>0.
You have a vertical asymptote at x = 1, no y-intercept, and the x-intercept is at x = 1+5^4. Can you sketch it now?
Another way to sketch it is to find its inverse y = 1+5^(x+4), and then reflect it about y = x to get f(x).