Isaac C. answered 10/15/15
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Let V be the required volume of hydrchloric acid solution.
The new volume will be 100 + V and the total amount of HCL in the solution is 36% (100 + V) = 36 + 0.36V
The amount of HCL in 100 mL at 30% = 30% * 100 = 30.
The amount of HCL in V ml of 60% = 60% * v = 0.6V
36 + 0.36V = 30 + 0.6V
6 = 0.24V v = 6/.24 = 25 mL