how do I solve the extraneous solution (8x+4)-10= -3

Question

I am working on extraneous solutions for my algebra 2 class

Answer 1

An extraneous solution is a slolution to the equation that does NOT work when you plug it into the equation.

8x+4-10=-3 so 8x -6 = -3 and therefore 8x = 3 then x = 3/8.

Now pllug 3/8 into the equation for x and we get 8(3/8) + 4 -10 = -3  or  3 +4 -10 = -3 which is true so there is NO extraneous solution.

Sure you wrote the right problem?