Ratio and Proportion

Question

Px/(b-c) = Qy/(c-a) = Rz/(a-b)

Find Pax + Qby + Rcz

Answer 1

Hi Prithvish,

 

Px/(b-c) = Qy/(c-a) =Rz/(a-b)

 

Px/ (b-c) = Rz/(a-b)                    Qy/(c-a) = Rz/(a-b)

 

Px = Rz (b-c)/ (a-b).......1               Qy = Rz(c-a)/(a-b).........2

 

substituting the value of Px & Qy from 1 & 2,we get

 

Pax + Qby +Rcz = Rza(b-c)/(a-b) +Rzb(c-a)/(a-b) +Rcz

 

                          =Rz[a(b-c)+b(c-a)+c(a-b)] /(a-b)

  

                           =Rz[ab-ac +bc-ba+ca-cb] / (a-b)

                           =0