F(x)=x squared + 6x +8

Question

find the y intercept, the equation of the axis of symmetry, an. The x-coordinate of the vertex.

Answer 1

F(x) = x² + 6x + 8

 

 

Since we need to find the axis of symmetry and the vertex, lets put F(x) in vertex form.

 

F(x) = a(x - h)² + h

 

where:

a = coefficient of x² term

 

The vertex is (h, k).

 

 

F(x) = (x² + 6x + 9) - 1

F(x) = (x + 3)² - 1

 

The vertex is  (-3, -1).

 

 

The x-coordinate of the vertex is -3

 

The axis of symmetry is    x = -3