how many moles of aluminum hydroxide are needed to neutralize 0.75 moles of hydrochloric acid

Question

How many moles of aluminum hydroxide are needed to neutralize 0.75 moles of hydrochloric acid 

Answer 1

Al(OH)₃ + 3HCl ----> AlCl₃ + 3H₂O

 

From this equation we know then that for each 3 mol of HCl we need 1 mol of Al(OH)₃ ... Hence by applying a factor we would say if 1 mol Al(OH)₃  is equivalent to 1 mol HCl then X is equivalent to 0.75 mol of HCl.... 

 

 

x = (0.75 x 1)/3 = 1/4 = 0.25 mol of Aluminum hydroxide.