
Huy D. answered 10/14/12
Experienced Math & CS Tutor
Hello Kirklin,
Most of the work here will be interpreting the problem and forming equations from the information given. Let's have it at step by step.
Store A: No matter what, you will be charged $18, so that needs to be in the equation. And then, you will be charged 2 cents, or $0.02 per copy. We don't know how many copies, so let's make that a variable called x. Then we get the equation:
A = 18 + 0.02x
So if you make one copy, it's $18.02, and if you make two copies, it's $18.04, and so on.
Store B: No matter what, you are charged $24, so that needs to be in the equation. And then, you will be charged 1.5 cents, or $0.015 per copy. We don't know how many copies, so let's make that a variable called x. Then we get the equation:
B = 24 + 0.015x
Once we have our two equations, we want both monthly costs to be the same. In other words, we want A = B, right?
A = B
Let's substitute in A:
18 + 0.02x = B
Now let's substitute in B:
18 + 0.02x = 24 + 0.015x
From here on it's algebra. Subtract 0.015x from both sides to get
18 + 0.005x = 24
Now subtract both sides by 18.
0.005x = 6
Dividing both sides by 0.005, we get:
x = 1200, or 1200 copies needed for the costs of store A and store B to be the same each month
________
Let's check our work
cost of A = 18 + 0.02 * 1200 = 18 + 24 = 42
cost of B = 24 + 0.015 * 1200 = 24 + 18 = 42
Both come out the same!