Edward C. answered 04/23/15
Tutor
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Caltech Grad for math tutoring: Algebra through Calculus
Let B = base price for 1 pound or less
Let S = surcharge for each additional pound over 1
So the Cost is equal to S*(Pounds - 1) + B
$33.00 for 7 pounds ==> 33.00 = S*(7-1) + B = 6*S + B
$74.25 for 22 pounds ==> 74.25 = S*(22-1) + B = 21*S + B
Subtract the top equation from the bottom one to cancel the B's and get
41.25 = 15*S
S = 2.75
Plug this value for S in to the 1st equation and solve for B
33.00 = 6*(2.75) + B = 16.50 + B
B = 16.50
So the base charge is $16.50 and the surcharge is $2.75 for each additional pound
Check: 7 pounds ==> C = 6*2.75 + 16.50 = 16.50 + 16.50 = $33.00
22 pounds ==> C = 21*2.75 + 16.5 = 57.75 + 16.50 = $74.25