clear fraction then solve by substitution

Question

1.subtract 5x^6-x^5

             2x^6+2x^5

            ----------------

2. clear fraction then solve by substitution

    x+1/2y=y-3

    1/4x-y=4x-y

Answer 1

1.

 

5x⁶ - x⁵ - (2x⁶ + 2x⁵) = 5x⁶ - x⁵ - 2x⁶ - 2x⁵ = 3x⁶ - 3x⁵

 

 

2.

 

First, clear the fractions by multiplying the first equation by 2 and the second by 4:

 

2x + y = 2y - 6

x - 4y = 16x - 4y

 

Then, simplify each expression by combining like terms:

 

2x - y = -6

-15x = 0

 

The second equation makes it clear that x = 0. So, substitute x = 0 into the first equation to find y:

 

2(0) - y = -6

-y = -6

y = 6