Use the Divergence Theorem to compute the surface integral where Q is the cube -1<=x<=1, -1<=y<=1, -1<=z<=1, F=<4y^2, 3z-cosx, z^3-x>. (Answer: 8)

The divergence of the vector field is 3z^2, which is what I found.

How to set up the integral and solve for it?

## Comments

Thank you.