ball shot upward; velocity; 67.50 m/s; How high is the cannon ball above the ground 4.30 seconds after it is fired? (Neglect air resistance.)

Question

A cannon ball is shot straight upward with a velocity of 67.50 m/s. How high is the cannon ball above the ground 4.30 seconds after it is fired? (Neglect air resistance.)

Answer 1

d = Vi(t) + (1/2)(g)(t^2)

d=67.5(4.3)+(-9.8)(4.3)^2/2

d=290-90.6

d=199m