Raymond B. answered 12/28/22
Math, microeconomics or criminal justice
L = w+5 meters
Perimeter = 82 = 2L+2w = 2(w+5) +2w = 2w+10+2w = 4w +10
4w +10 = 82
4w = 82-10= 72
w = 72/4 = 18 meters wide
L =w+5=18+5 = 23 meters long
Makoto E.
asked 01/27/21Be sure to use proper algebra communication to write your solution. The length of a rectangle is 5 m longer than the width. The perimeter of the rectangle is 82 m. Find the length and the width of the rectangle.
Raymond B. answered 12/28/22
Math, microeconomics or criminal justice
L = w+5 meters
Perimeter = 82 = 2L+2w = 2(w+5) +2w = 2w+10+2w = 4w +10
4w +10 = 82
4w = 82-10= 72
w = 72/4 = 18 meters wide
L =w+5=18+5 = 23 meters long
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