Raymond B. answered 01/05/23
Math, microeconomics or criminal justice
F = 14 +S where F and S are speeds of the First and Second cars
132=Ft where t is the same time traveled for both cars
distance = speed times time
90=St
132=(14+S)t
132/90 = (14+S)t/St = (14+S)/S=22/15
22S = 15(14+S)
22S -15S = 15(14)
7S = 210
S = 210/7 =30 mph= Second car's speed
F= 44 mph= First car's speed
t = time = 90/30 = 3 hours
44x3= 132
30x3=90