For the following reaction, 4.44 grams of silver nitrate are mixed with excess copper(II) chloride. The reaction yields 2.50 grams of silver chloride.

Question

silver nitrate (aq) + copper(II) chloride (s) silver chloride (s) + copper(II) nitrate (aq)

What is the theoretical yield of silver chloride ?

What is the percent yield of silver chloride ?

Answer 1

1. Determine how many moles of silver you had initially
2. moles=mass/molar mass so in this case 4.44g/170g/mole = 0.026moles
3. As 1 mole of silver nitrate makes 1 mole of silver chloride, convert moles to mass of silver chloride
4. mass=moles*molar mass so in this case 0.0261moles * 143g/mole = 3.73g
5. Percent yield = actual yield / theoretical yield or here 2.5g/3.73g * 100 = 67%