
Cynthia M. answered 03/11/13
UC Berkeley Educated Tutor with Patience and Creativity
First of all, you need to prove that the distances are all part of a right triangle. Cardinal directions such as north and east are perpendicular to each other on a compass. This proves that the angle formed between walk north and east is 90 degrees. As x and 2x+4 intersect at this 90 degree angle then it must be deduced that 2x+6 is the length of the hypotenuse. This is where we derive that in the Pythagorean theorem c is always the long hypotenuse so it must be that c=2x+6. It does not matter whether x is a or b because both parts are interchangeable.
So the equation states, let a=x, b=2x+4 and c=2x+6.
Plug these conditions into the Pythagorean Theorem and solve.
a^2+b^2=c^2
x^2+(2x+4)^2=(2x+6)^2
x^2+(2x+4)(2x+4)=(2x+6)(2x+6)
x^2+4x^2+16x+16=4x^2+24x+36
-4x^2 -24x -36 -4x^2 -24x -36
x^2-8x-20=0
(x+2)(x-10)=0
x=-2, 10
x can not be negative, so x=10