Can I get help with this problem?

Question

The vertex of parabola is (-2,-20), and its y-intercept is (0,-12)

The equation of the parabola is y= ____ x² + _____ x + ____

Answer 1

Use the vertex form:

y = a(x-h)² + k

where (h, k) = (-2,20) is the location of the vertex and a is a constant.

y = a(x-(-2))² + 20

y = a(x+2)² + 20

To find the value of the constant, a, plug in the x and y values from the y-intercept, (0, -12):

-12 = a(0+2)² + 20

-32 = 4a

-8 = a

y = -8(x+2)² + 20

The problem statement wants the answer in standard form, not vertex form. Multiply the vertex form of the equation out and combine like terms to put it into standard form.