What is the molar concentration of NaCl in a solution containing 4.65 g of NaCl in 300.00mL of solution?

Answer 1

Molarity = moles of solute / Liters of solution

mol NaOH = 4.65 g x (1 mol NaCl / 58.44 g NaCl) = 0.0796 mol NaCl

Volume of solution in Liters = 300.00 mL x (1 L / 1000 mL) = 0.30000 L

Molarity = 0.0796 / 0.30000 = 0.265 M