Lauren H. answered 09/16/18
Tutor
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Experienced High School Chemistry Teacher
how many milliliters of 5% hydrochloric acid solution should be added to 60 milliliters of a 10% hydrochloric acid solution to obtain an 8% solution
xmL(5) + 60 mL(10) = (x + 60)(8)
5x + 600 = 8x + 480
3x = 120
x = 40mL