stephanie had a total of 80 2$ and 10$ bills after spending 2/5 of the 2$ bills and 8 of the 10$ bill she had an = amount of 10 and 2$ bills

Question

how much money did stephanie have in the beginning

Answer 1

X+Y = 80  --->  Y = 80 - x

 

(3/5)X  = Y-8 <--- after spending 2/5 of the $2 bills, there are 3/5 of them remaining,

                                which is equal to 8 less than number of $10 bills

 

 

 

(3/5)X = 80 - x - 8

 

(3/5)X = 72 - x

 

(3/5)X = 72 - (5/5)X

 

(8/5)X = 72

 

X = 72*5/8 = 9*5 = 45

 

There are 45 $2 bills and 35 $10 bills.