J.R. S. answered 04/25/18
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Ph.D. in Biochemistry--University Professor--Chemistry Tutor
Colligative properties:
∆T = imK
∆T = change in freezing point = ?
i = van't Hoff factor = 1 for C2H6O2 (a non electrolyte; probably ethylene glycol, i.e. antifreeze)
m = molality = moles solute/kg solvent = 54g/62g/mol/0.215 kg = 4.05 m
K = freezing constant = 1.86
∆T = (1)(4.05)(1.86) = 7.5 degrees C
Freezing point of the solution would be -7.5 degrees C