
Mark M. answered 02/22/18
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Mathematics Teacher - NCLB Highly Qualified
A = (1/2)(B + C + D) ⇒ 2A = B + C + D
B = (1/3)(A + C + D) ⇒ 3B = A + C + D
C = (1/4)(A + B + D) ⇒ 4C = A + B + D
C = (1/4)(A + B + D) ⇒ 4C = A + B + D
D = 78
Substitute 78 for D. Solve the three equations in three variables