AGE OF A FATHER 4 TIMES OF HIS SON. IF HIS SON 36 YEARS YOUNGER THAN FATHER. WHAT IS THEIR AGE?

Question

I AM A STUDENT I HAVE NO TUTOR. WANT HELP REGARDING MATH PROBLEM

Answer 1

Let f = father's age

Let s = son's age

 

Age of father is 4 times that of his son:  f = 4s

 

Son is 36 years younger than father:  s = f-36

 

Use substitution, replace f with 4s in second equation and solve.

s = 4s - 36

subtract 4s from both sides

-3s = -36

divide both sides by -3

s = 12

 

The son is 12 years old.

Since the father is 4 times as old. Father is 4(12) = 48 years old.