airplane accelerates at 3.2 m/sec2 travels 32.8 seconds to takeoff how far did it travel to take off

Question

Airplane accelerates at 3.2 m/ sec2 for 32.8 seconds to tale off.  What is the dustance to takeoff?

Answer 1

I noticed the student reworded the question to say the airplane ACCELERATES at 3.2 m/s².  With this change to the question, the answer becomes:

 

d = v₀t + at²/2

 

If the airplane started from rest, then

 

v₀ = 0

 

d = at²/2 = (1/2)(3.2 m/s²)(32.8 s)² ≅ 1721 m

Answer 2

distance = speed x time

speed = acceleration x time Utilized these two formulas.