
Philip P. answered 12/03/17
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Use the factored form of a quadratic expression:
a(x-p)(x-q)
- a = a constant
- p and p are the x-intercepts = -2 and 5
a(x+2)(x-5)
There are an infinite number of parabolas that have these two intercepts, so a could be any number. To figure out what value a actually has, you would need one additional point on the graph. Without that point, a could be any number (so assume it's a=1).
Multiply the above expression out to put it into standard (ax2+bx+c) form.
Linea D.
12/03/17