Mark B. answered 11/16/17
Tutor
New to Wyzant
PhD Candidate in Psychology: Experienced Math, Statistics, Tutor
Hello Brian,
To solve this problem you only need to remember a few things:
First: You need the formula I presume since it is Algebra I
Second: You need to know what each symbol stands for in the formula, right?
So, here is the formula:
A = P (1 + r/n) ^n*t
A = total amount
P = Principal of amount deposited
r = annual rate of interest
n = number of times compounded
t = time in years
In the problem you were given:
P = 1000 r = 6% n = 1 (compounded annually) t = 1 (assuming the problem is asking how much money will accumulate after 1 year. If this number is different than 1 year and you did not share that part, just plug in the correct number)
Once we plug in the information, we have:
A = 1000(1 + 0.06/1) ^ 1*1
Solve the problem with BODMAS procedure:
B = brackets, O = Powers. D = Division, M = Multiplication A = Addition, S = Subtraction
Therefore:
A = 1000 (1 + .06) ^ 1*1
A = 1000 (1.06)^1*1
A = 1000 (1.06) ^1
A = 1000 (1.06)
A= $1,060
Again: I am ASSUMING the number of years to be ONE because no other information was provided in the problem. If this was by accident, simply substitute the 1 in the powers portion of the equation for the correct number of years.
I hope I have helped you this morning. Have a great day.
To solve this problem you only need to remember a few things:
First: You need the formula I presume since it is Algebra I
Second: You need to know what each symbol stands for in the formula, right?
So, here is the formula:
A = P (1 + r/n) ^n*t
A = total amount
P = Principal of amount deposited
r = annual rate of interest
n = number of times compounded
t = time in years
In the problem you were given:
P = 1000 r = 6% n = 1 (compounded annually) t = 1 (assuming the problem is asking how much money will accumulate after 1 year. If this number is different than 1 year and you did not share that part, just plug in the correct number)
Once we plug in the information, we have:
A = 1000(1 + 0.06/1) ^ 1*1
Solve the problem with BODMAS procedure:
B = brackets, O = Powers. D = Division, M = Multiplication A = Addition, S = Subtraction
Therefore:
A = 1000 (1 + .06) ^ 1*1
A = 1000 (1.06)^1*1
A = 1000 (1.06) ^1
A = 1000 (1.06)
A= $1,060
Again: I am ASSUMING the number of years to be ONE because no other information was provided in the problem. If this was by accident, simply substitute the 1 in the powers portion of the equation for the correct number of years.
I hope I have helped you this morning. Have a great day.