The polynomial of degree 3 3, P ( x ) P(x), has a root of multiplicity 2 2 at x = 2 x=2 and a root of multiplicity 1 1 at x = − 2 x=-2. The y y-intercept

Question

help me find the formula of P(x)

Answer 1

3rd degree polynomial, x=2 root multiplicity 2, root at x = -2

 

p(x) = A(x-2)²(x+2)

Note the multiplicity 2 at the root for x=2.

Note that A is just some number factorable from each term of p(x)

 

p(x) = A(x²-4x+4)(x-1)

 

You can finish multiplying / expanding p(x) if needed.

 

y-Intercept:  Set x=0 and solve for p(x)

 

y = A(4)(-1) = -4A

 

If the value of A is 1, then the y-intercept is the point (0, -4)

Answer 2

P(x) = A(x - 2)²(x + 2)

 

A ≠ 0

 

The information on the y-intercept is missing, which we need to find A and finish the solution.  Also, note how things are appearing in double in the problem statement.  I suggest you edit the problem statement, remove the doubles, and add the missing y-intercept.