
Kevin S. answered 01/24/13
Tutor
5
(4)
Assuming the problem is x = log 152/3:
The argument of a log raised to a power is the same as the power times the log function, or:
log 152/3 = (2/3) log 15
To determine log 15, I'll refer to my calculator and I get 1.17609. Mutliply by 2/3 to get 0.78406
So 0.78406 = log 152/3