Write an equation for a line parallel to y=-3x+1 and passing through the point (3,-5)

Question

Write an equation for a line parallel to y=-3x+1 and passing through the point (3,-5)

Answer 1

y = -3x+1 has a slope of -3. Since parallel lines have equal slopes, the new line will also have a slope of -3.

You now have a point and a slope, so use the Point-Slope Form for the equation of a line.

y - y₁ = m(x - x₁)

y + 5 = -3(x - 3)

y + 5 = -3x + 9

y = -3x + 4

Answer 2

It must have the same slope as the given line, so

 

m = - 3

 

In point-slope form,

 

y - y₁ = m(x - x₁)

 

y₁ = -5

x₁ = 3

 

y - (-5) = -3(x - 3)

 

y + 5 = -3(x - 3)